There are n stones on the direct line. You are given an array stones of length n where stones[i] is the position of the ith stone. Initially, the frog is on the first stone and wants to reach the last stone. In one step, the frog can jump to the next stone. More formally, if the frog is at stones[i], it can jump to stones[j] where i

Question

There are n stones on the direct line. You are given an array stones of length n where stones[i] is the position of the ith stone. Initially, the frog is on the first stone and wants to reach the last stone. In one step, the frog can jump to the next stone. More formally, if the frog is at stones[i], it can jump to stones[j] where i < j. However, there is a limitation on the frog's jump. Let maxJump be the maximum jump the frog has made so far. The frog can only jump to stones[i] if stones[j] - stones[i] <= 2 * maxJump. Return the minimum possible value of maxJump to reach the last stone starting from the first stone.

Accepted Answer

Frog Jump problem involves calculating the minimum number of jumps needed to reach a target position from a starting position.

The frog starts at position 0 and can jump to any position within its jump range.
The target position is given, and the frog can jump either 1 or 2 units at a time.
Example: If the target is 5, the frog can jump 1+1+1+1+1 or 2+2+1, totaling 5.
Dynamic programming can be used to optimize the solution by storing previously calculated jumps.

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