Compute the nearest larger number by interchanging its digits.
Given two numbers a and b
Find the smallest number greater than b by interchanging the digits of a
If not possible, print -1

Question

Compute the nearest larger number by interchanging its digits updated.Given 2 numbers a and b find the smallest number greater than b by interchanging the digits of a and if not possible print -1.

Accepted Answer

Compute the nearest larger number by interchanging its digits.

Given two numbers a and b
Find the smallest number greater than b by interchanging the digits of a
If not possible, print -1

Accepted Answer

from itertools import permutations

def nearest_larger_number(a, b):
    digits = [int(d) for d in str(a)]
    all_permutations = list(permutations(digits))
    all_numbers = [int(''.join(map(str, p))) for p in all_permutations]
    result = -1
    for num in all_numbers:
        if num > b and (result == -1 or num < result):
            result = num
    return result

a = int(input())
b = int(input())
print(nearest_larger_number(a,b))

Asked in TCS

Compute the nearest larger number by interchanging its digits updated.Given 2 numbers a and b find the smallest number greater than b by interchanging the digits of a and if not possible print -1.

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